The intensity of the light coming from one of the slits in Young’s experiment is twice the intensity of the light coming

Given : I₁:I₂ = 2:1

If E₁₀ and E₂₀ are the amplitudes of the interfering waves, the ratio of the maximum intensity to the minimum intensity in the fringe system is

\(\frac{I_{max}}{i_{min}}=(\frac{E_{10}+E_{20}}{E_{10}-E_{20}})^2 =(\frac{r+1}{r-1})^2\)

where r = E₁₀/E₂₀.

∴ \(\frac{I_1}{I_2}=(\frac{E_{10}}{E_{20}})^2=r^2\)

∴ r =\(\sqrt{\frac{I_1}{I_2}}\)

∴ \(\frac{I_{max}}{i_{min}}=(\frac{\sqrt{2}+1}{\sqrt{2}-1})^2=(\frac{2.414}{0.414})^2\) = (5.83)² = 33.99 = 34

The ratio of the intensities of the bright and dark fringes in the resulting interference pattern is 34 : 1.