Show that the function f : R → R given by f(x) = x³ is injective.

HelloWorld Asked 22 Oct 2022 Student doubt Save WhatsApp Report

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f(x) = x³

⇒ f(x1) = f(x2)

⇒ x³1 = x³1

⇒ x1 = x2

⇒ f is one-one, i.e., f is injective.

HelloWorld · 22 Oct 2022 Report

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