Question

The probability of obtaining an even prime number on each die, when a pair of dice is rolled is

(A) 0

(B) $\frac{1}{3}$

(C) $\frac{1}{12}$

(D) $\frac{1}{36}$

Answer 1

There are only one even prime number, i.e., 2, when a dice is rolled, the probability of getting an even prime number = $\frac{1}{6}$.

When two dice are rolled, the probability of getting an even prime number on each dice = $\frac{1}{6}$ × $\frac{1}{6}$ = $\frac{1}{36}$