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A 12pF capacitor is connected to a 50V battery. How much electrostatic energy is stored in the capacitor?
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C = 12 pF, V = 50V
E = \(\frac { 1 }{ 2 }\)CV²
= \(\frac { 1 }{ 2 }\) x 10-12 x 50 x 50
= 150 x 10-10
= 1.5 x 10-8 J

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