0 votes
142 views
in Chapter 2 Electrostatic Potential and Capacitance by (98.9k points)
edited

A parallel plate capacitor with air between the plates has a capacitance of 8 pF (lpF = 10-12F). What will be the capacitance if the distance between the plates is reduced by half, and the space between them is filled with a substance of dielectric constant 6?

1 Answer

0 votes
by (98.9k points)
selected by
 
Best answer

C = 8pF,
C = \(\frac{\varepsilon_{0} \mathrm{~A}}{\mathrm{~d}}\)
C' = \(\frac{\varepsilon_{\mathrm{r}} \varepsilon_{0} \mathrm{~A}}{\frac{\mathrm{d}}{2}}\)
= 2εr
∴ C' = 2 x 6 x 8 x 10-12 F = 96 pF

Related questions

Doubtly is an online community for engineering students, offering:

  • Free viva questions PDFs
  • Previous year question papers (PYQs)
  • Academic doubt solutions
  • Expert-guided solutions

Get the pro version for free by logging in!

5.7k questions

5.1k answers

108 comments

537 users

...