Geometry
- A person is standing at a distance of 80m from a church looking at its top. The angle of elevation is of 45°. Find the height of the church Correct Answer is 80 m 1
- proove that tan theta\sec theta - 1= tan theta + sec theta + 1/ tan theta + sec theta - 1} Hence , prooved 2
- Prove That: Sec 4 a ( 1 − Sin 4 a ) − 2 Tan 2 a = 1 Hence , prooved 2
- Prove That: Tan a ( 1 + Tan 2 a ) 2 + Cot a ( 1 + Cot 2 a ) 2 = Sin a Cos a Hence , prooved 2
- If tanθ+ 1/tanθ =2 thenshow that tan ^2 θ+ 1/ tan^2θ=2 Hence prooved 2
- proove that viii. } secθ+tanθ=cosθ/(1−sinθ) Hence , prooved 2
- Proove that vii. sin^4 θ – cos^4 θ = 1 – 2 cos^2 θ Hence , prooved 2
- prove that vi ) 1/secθ−tanθ=secθ+tanθ Hence , prooved 2
- proove that v. cot θ + tan θ =cosec θ. sec θ Hence , prooved 2
- proove that iv. (sec θ – cos θ) (cot θ + tan θ)= tan θ. sec θ Hence , prooved 2
- Prove that √1-sinθ/1+sinθ=secθ−tanθ Hence , prooved 2
- prove that cos^2 θ (1+ tan2 θ) = 1 Hence , prooved 2
- prove that sin^2θ/cosθ+cosθ=secθ Solution is in img format 2
- If tan θ = 1, then find the value of sinθ+ cosθ /secθ+cosecθ value of equation is 1/2 1
- If 5 sec θ – 12 cosec θ = θ, find the values of sec θ, cos θ and sin θ. Values of secθ is 13/ 5 , cos theta is 5/13 and sin theta is 12/13 1
- If cot θ = 40/9, find the values of cosec θ and sin θ Correct answer for cosec θ is 41/9 and for sinθ is 9/41 1
- If tan θ = 3/4, find the values of sec θ and cos θ. Correct answer for secθ=5/4 and cosθ=4/5 Solution:: 1
- If sin θ = 7/25, find the values of cos θ and tan θ. Value of cosθ is 24/25 , tanθ=7/24 Solution:: 1
- Trigonometry notes std 10th maharashtra board pdf english medium exercise 6.1 Download pdf for offline study , If you have any doubt just use Brainiak live doubt support {only for registered users for free} Download 1
- In ∆ABC, ray BD bisects ∠ABC and ray CE bisects ∠ACB. If seg AB = seg AC, then prove that ED || BC Watch complete video and understand https://youtu.be/MGVjoeMgblM 2
- In the adjoining figure, X is any point in the interior of triangle. Point X is joined to vertices of triangle. Seg PQ || seg DE, seg QR || seg EF. Watch till end and understand topic https://youtu.be/GKMhr5NSd8U 2
- In ∆ABC,seg BD bisects ∠ABC. If AB = x,BC x+ 5, AD = x – 2, DC = x + 2, then find the value of x. x=10 https://youtu.be/qmV-xkI5hlQ 2
- In ∆LMN, ray MT bisects ∠LMN. If LM = 6, MN = 10, TN = 8, then find LT. Correct Answer is LT=4.8 units https://youtu.be/V6lBZ3c0Hjw 2
- In the adjoining figure, if AB || CD || FE, then find x and AE. Correct answer is x=6 and AE=18 units https://youtu.be/40WyRKKZ-P0 1