#jee 2022
- A circle of equation x2+y2+ax+by+c= 0 passes through (0, 6) and touches y=x2 at (2, 4). Find a+c. Answer :: 16 Solution :: Given ,x²+y²+ax+by+c= 0 passes through (0, 6) Then , 0+36+0+6b+c=0 6b-+c=-36 ....(1) Touches y=x² at (2, 4) 4+16+2a... 2
- Stopping potential for e- for wavelength 491 nm is 0.410 V incidence wavelength is changed to new value It D Bro 1240 / 1.92 =645.83 2
- A ball when thrown up from a tower of height h takes 6 seconds to reach ground and when thrown downward with same Correct option is A) 3 sec 2
- If one end of vertical spring is connected to the ground and other end is connected to horizontal platform at rest. Correct option is A) 120mg 2
- At what height from the surface of earth the weight of the body is 1/3rd of its weight at the surface? Answer is C) 4684.8 km 2