**Given:**

- 80% of the students like English
- 30% of the students like both English and Mathematics

**We want to find:**

- The percentage of students who like Math, also like English

**Solution:**

We can use the formula for conditional probability to solve this problem:

```
P(A|B) = P(A and B) / P(B)
```

where:

- P(A|B) is the probability of event A happening given that event B has already happened
- P(A and B) is the probability of both events A and B happening
- P(B) is the probability of event B happening

In this case, we want to find P(Math|English), which is the probability of a student liking Math given that they like English. We know that P(English) = 0.8 and P(English and Math) = 0.3. Plugging these values into the formula, we get:

```
P(Math|English) = 0.3 / 0.8 = 0.375
```

Converting this to a percentage, we get:

```
P(Math|English) = 0.375 * 100% = 37.5%
```

Therefore, 37.5% of the students who like English also like Math.