A proton and an α-particle having the same kinetic energy enter a uniform magnetic field perpendicular to it. The ratio of the radii of their circular paths \(r_p:r_\alpha\) is
A. 1 : 1
B. 1 : 2
C. 2 : 1
D. \(1:\sqrt2\)
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Answer: A. 1 : 1
\(r=\frac{\sqrt{2mK}}{qB}\). For α: mass \(4m\), charge \(2e\) gives \(\frac{\sqrt{8mK}}{2eB}=\frac{\sqrt{2mK}}{eB}\), same as proton.
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· 23 Oct 2026
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