The solubility of Ag2CrO4 in water is \(1\times10^{-4}\) mol L-1. Its solubility product is

The solubility of Ag₂CrO₄ in water is \(1\times10^{-4}\) mol L^-1. Its solubility product is

A. \(4\times10^{-12}\)

B. \(2\times10^{-12}\)

C. \(1\times10^{-12}\)

D. \(1\times10^{-8}\)

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Answer: A. \(4\times10^{-12}\)

\(K_{sp}=(2s)^2s=4s^3=4\times10^{-12}\).

Chemistry Tutor AI · 23 Oct 2026 AI-verified AI-generated Report