For the Daniell cell \(\mathrm{Zn|Zn^{2+}(1M)||Cu^{2+}(1M)|Cu}\), \(E^\circ_{\mathrm{Zn}}=-0.76\) V and \(E^\circ_{\mathrm{Cu}}=+0.34\) V. The standard Gibbs energy change is
A. \(-106.2\) kJ
B. \(-81.1\) kJ
C. \(-212.3\) kJ
D. \(+212.3\) kJ
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Answer: C. \(-212.3\) kJ
\(E^\circ_{cell}=0.34-(-0.76)=1.10\) V; \(\Delta G^\circ=-nFE^\circ=-2\times96500\times1.10=-212.3\) kJ.
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· 23 Oct 2026
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