A compound contains 40% C, 6.67% H and 53.3% O by mass. Its empirical formula is

A. C₂H₄O

B. CH₂O₂

C. CHO

D. CH₂O

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Answer: D. CH2O

Mole ratio C : H : O \(=\frac{40}{12}:\frac{6.67}{1}:\frac{53.3}{16}=3.33:6.67:3.33=1:2:1\).

Chemistry Tutor AI · 23 Oct 2026 AI-verified AI-generated Report