Some Basic Concepts of Chemistry
Chapter 1: Some Basic Concepts of Chemistry , maharashtra state board 11th textbook
Top questions
See all →- E. A student used a carbon pencil to write his homework. The mass of this was found to be 5 mg. With the help of this calculate. Given : mass of carbon = 5mg = 5× 10⁻³ g Atomic mass of carbon=12u Solution :: a. The number of moles of carbon in his homework writing numb... 1
- M.In two moles of acetaldehyde (CH3 CHO) calculate the following a. Number of moles of carbon b. Number of moles of hydrogen a) Number of moles of carbon 1 molecule of CH3CHO contains 2 C-atoms. Therefore, 2 mol of CH3CHO contains 2×2 = 4 moles of Carbon. b) Number... 1
- A. What is the ratio of molecules in 1 mole of NH3 and 1 mole of HNO3 . Correct answer is 1:1 one mole of any substance,compound , or elements contain particles equal to avagadro's number i.e. 6.022 × 10²³ theref... 1
- B. Calculate number of moles of hydrogen in 0.448 litre of hydrogen gas at STP Given : volume of hydrogen at STP =0.448 L To find : number of moles of hydrogen Formula : number of moles of a gas = Volumespace of space a... 1
- F. Arjun purchased 250 g of glucose (C6 H12O6 ) for Rs 40. Find the cost of glucose per mole Given : cost for 250 g glucose = Rs 40 , formula of glucose = C₆H₁₂O₆ To find : cost of glucose per mole solution: molecular formula of gluc... 1
- G. The natural isotopic abundance of 10B is 19.60% and 11B is 80.40 %. The exact isotopic masses are 10.13 and 11.009 respectively. The answer is 10.81 u Solution : Relative abundance of ¹⁰B isotope = 19.60% Relative abundance of ¹¹B isotope = 80.40% Averagespace atomic s... 2