The absolute minimum value of \(f(x)=x^3-3x\) on \([0,3]\) is
A. −3
B. 0
C. −2
D. 2
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Answer: C. −2
\(f'(x)=3x^2-3=0\Rightarrow x=1\). \(f(0)=0,\ f(1)=-2,\ f(3)=18\). Minimum \(=-2\).
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· 23 Oct 2026
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