Q.11 The displacement of a particle at a time t is given by s=2t³-5t²+4t-3 . Find the time when acceleration is 14 ft/sec².

Answer: t=2 seconds Velocity v=ds/dt=6t²-10t+4 . Acceleration a=dv/dt=12t-10 . When a=14 : 12t-10=14⇒ t=2 . The acceleration is 14 ft/sec² after 2 seconds.

Chapter: Applications of Derivatives· Mathematics & Statistics Part 2

The displacement of a particle at a time \(t\) is given by \(s=2t^3-5t^2+4t-3\). Find the time when acceleration is 14 ft/sec2.

Q.11 The displacement of a particle at a time \(t\) is given by \(s=2t^3-5t^2+4t-3\). Find the time when acceleration is 14 ft/sec².

Doubtly Asked 29 Oct 2026 Board exam · July 2024 hsc 12th Save WhatsApp Report

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Answer: \(t=2\) seconds

Velocity \(v=\dfrac{ds}{dt}=6t^2-10t+4\). Acceleration \(a=\dfrac{dv}{dt}=12t-10\).

When \(a=14\): \(12t-10=14\Rightarrow t=2\). The acceleration is 14 ft/sec² after 2 seconds.

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report

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The displacement of a particle at a time \(t\) is given by \(s=2t^3-5t^2+4t-3\). Find the time when acceleration is 14 ft/sec2.

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