The radius of a circle increases at 0.5 cm/s. The rate of increase of its area when the radius is 4 cm is
A. \(4\pi\) cm2/s
B. \(2\pi\) cm2/s
C. \(8\pi\) cm2/s
D. \(16\pi\) cm2/s
A. \(4\pi\) cm2/s
B. \(2\pi\) cm2/s
C. \(8\pi\) cm2/s
D. \(16\pi\) cm2/s
Best answer
Answer: A. \(4\pi\) cm2/s
\(\frac{dA}{dt}=2\pi r\frac{dr}{dt}=2\pi(4)(0.5)=4\pi\).
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