The equation of the tangent to \(y=x^2-2x+3\) at \(x=2\) is
A. \(y=2x-3\)
B. \(y=2x-1\)
C. \(y=x+1\)
D. \(y=2x+1\)
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Answer: B. \(y=2x-1\)
Point (2,3); slope \(=2x-2=2\). Tangent: \(y-3=2(x-2)\Rightarrow y=2x-1\).
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· 23 Oct 2026
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