A bacterial population grows at a rate proportional to its size and doubles in 2 hours. The time in which it becomes 8 times the original is
A. 16 hours
B. 6 hours
C. 4 hours
D. 8 hours
A. 16 hours
B. 6 hours
C. 4 hours
D. 8 hours
Best answer
Answer: B. 6 hours
\(N=N_0e^{kt}\), \(e^{2k}=2\). \(8=2^3\Rightarrow t=3\times2=6\) h.
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