Skip to content
doubtly

1 answer

Best answer

Answer: A. \(x^4\left(\dfrac{dy}{dx}\right)^2-x\dfrac{dy}{dx}-y=0\)

Answer: (a) \(x^4\left(\dfrac{dy}{dx}\right)^2-x\dfrac{dy}{dx}-y=0\)

Differentiating, \(\dfrac{dy}{dx}=-\dfrac{c}{x^2}\), so \(c=-x^2\dfrac{dy}{dx}\).

Substituting in \(y=c^2+\dfrac cx\): \(y=x^4\left(\dfrac{dy}{dx}\right)^2-x\dfrac{dy}{dx}\), i.e. \(x^4\left(\dfrac{dy}{dx}\right)^2-x\dfrac{dy}{dx}-y=0\).

Doubtly AI · 29 Oct 2026 AI-generated · not yet verified Report
Was this answer helpful?

Your answer

Log in or create a free account to answer this question.