Answer: m∠ADB = 128º
A radius is perpendicular to the tangent at the point of contact, so ∠DAC = ∠DBC = 90º.
The sum of the angles of quadrilateral ADBC is 360º: ∠ADB = 360º – 90º – 90º – 52º = 128º.
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Answer: m∠ADB = 128º
A radius is perpendicular to the tangent at the point of contact, so ∠DAC = ∠DBC = 90º.
The sum of the angles of quadrilateral ADBC is 360º: ∠ADB = 360º – 90º – 90º – 52º = 128º.
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