Answer: \(\cos\theta = \dfrac{60}{61}\)
\(\sin^2\theta + \cos^2\theta = 1\)
\(\cos^2\theta = 1 - \dfrac{121}{3721} = \dfrac{3600}{3721}\)
\(\cos\theta = \dfrac{60}{61}\) (taking θ acute).
Best answer
Answer: \(\cos\theta = \dfrac{60}{61}\)
\(\sin^2\theta + \cos^2\theta = 1\)
\(\cos^2\theta = 1 - \dfrac{121}{3721} = \dfrac{3600}{3721}\)
\(\cos\theta = \dfrac{60}{61}\) (taking θ acute).
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