For an A.P., \(a = 2\) and \(d = 3\). Then \(t_5 = \)
A. \(14\)
B. \(17\)
C. \(11\)
D. \(15\)
A. \(14\)
B. \(17\)
C. \(11\)
D. \(15\)
Best answer
Answer: A. \(14\)
\(t_n = a + (n-1)d\), so \(t_5 = 2 + 4 \times 3 = 14\).
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