Skip to content
doubtly

Arithmetic Progression

Arithmetic Progression

130 solved questions 1 note 2 tests 1 video

Take chapter test ← Previous Next chapter →

Every question from past board papers on Arithmetic Progression, newest paper first. Open any question for its full worked answer.

Maharashtra SSC Algebra (Mathematics Part I) Board Paper June 2026

Full paper →
  1. Q.1 (B)(ii) Find the first term and common difference of the given A.P. 5, 1, –3, –7, ……

    1 mark · See worked answer →

  2. Q.3 (A)(ii) Complete the following activity to find, ‘how many three digit natural numbers which are divisible by 5’.

    Activity :

    Three digit natural numbers divisible by 5 are as follows :
    100, 105, 110, ……………, 995.

    \(t_n = \) ____, \(a = \) ____, \(d = 5\), \(n = ?\)

    \(t_n = a + (n - 1)d\) …………… formula

    \(995 = \) ____ \(+ (n - 1) \times \) ____

    \(895 = (n - 1) \times 5\)

    \(\dfrac{895}{5} = n - 1\)

    ____ \(+ 1 = n\)

    ____ \(= n\)

    \(\therefore\) There are 180 three digit natural numbers, divisible by 5.

    3 marks · See worked answer →

  3. Q.4 (iii) Ajay Sharma repays the borrowed amount of ₹ 3,25,000 by paying ₹ 30,500 in the first month and then decreases the payment by ₹ 1,500 every month. How long will it take to clear his amount ?

    4 marks · See worked answer →

Maharashtra SSC Algebra (Mathematics Part I) Board Paper March 2026

Full paper →
  1. Q.1 (A)(iv) Sum of first five multiples of 3 is ....................... .

    1 mark · See worked answer →

  2. Q.2 (A)(ii) Write the correct number in the given boxes from the given A.P. : 70, 60, 50, 40, ............

    Here \(t_1 =\) ____, \(t_2 = 60\), \(t_3 =\) ____
    \(\therefore a =\) ____, \(d =\) ____

    2 marks · See worked answer →

  3. Q.2 (B)(iv) Given A.P. is 12, 16, 20, 24, .................... Find the 24th term of this progression.

    2 marks · See worked answer →

  4. Q.3 (B)(ii) Sachin invested some amount in a National Saving Certificate Scheme. In the first year he invested ₹ 5,000, in the second year ₹ 7,000, in the third year ₹ 9,000 and so on. Find the total amount that he invested in 12 years.

    3 marks · See worked answer →

Maharashtra SSC Algebra (Mathematics Part I) Board Paper March 2025

Full paper →
  1. Q.1 (A)(iii) Find the common difference of the following A.P. : 4, 4, 4, ...

    1 mark · See worked answer →

  2. Q.1 (B)(ii) Find the first term of the given sequence : \(t_n = 3n - 4\).

    1 mark · See worked answer →

  3. Q.2 (B)(iii) Find the 19th term of the following A.P. : 7, 13, 19, 25, ...

    2 marks · See worked answer →

  4. Q.4 (ii) A farmer borrows ₹ 1,000 and agrees to repay with a total interest of ₹ 140, in 12 instalments. Each instalment being less than the preceding instalment by ₹ 10. What should be the amount of his first and last instalment ?

    4 marks · See worked answer →

Maharashtra SSC Algebra (Mathematics Part I) Board Paper July 2025

Full paper →
  1. Q.1 (A)(iii) For given A.P. \(a = 3.5\), \(d = 0\), then \(t_2\) = .........................

    1 mark · See worked answer →

  2. Q.2 (B)(iii) Which term of the following A.P. is 560 ?

    2, 11, 20, 29, .......

    2 marks · See worked answer →

  3. Q.3 (A)(i) In an A.P. sum of three consecutive terms is 27 and their product is 504. Complete the following activity to find the terms.

    Activity :

    Let three consecutive terms be \(a - d\), \(a\), \(a + d\).

    \(\therefore\ a - d + a + a + d =\) ____

    \(\therefore\ a =\) ____

    Similarly :

    \((a - d) \times a \times (a + d) =\) ____

    \(\therefore\ [(9)^2 - d^2] \times 9 = 504\)

    \(\therefore\ (81 - d^2) \times 9 = 504\)

    \(\therefore\ d^2 = 81 -\) ____

    \(\therefore\ d = \pm 5\)

    Thus by putting \(a = 9\) and \(d = 5\) we get three consecutive terms = ____

    Or by putting \(a = 9\) and \(d = -5\) we get three consecutive terms = ____

    3 marks · See worked answer →

  4. Q.5 (ii) If first term of an A.P. is ‘\(p\)’, second term is ‘\(q\)’ and last term is ‘\(r\)’, then show that the sum of all terms is \(\dfrac{(p + r)(q + r - 2p)}{2(q - p)}\).

    3 marks · See worked answer →

Maharashtra SSC Algebra (Mathematics Part I) Board Paper July 2024

Full paper →
  1. Q.1 (A)(iii) The sequence –10, –6, –2, 2, ............... .

    1 mark · See worked answer →

  2. Q.1 (B)(ii) Find the first term and common difference for the following A.P. : 5, 1, –3, –7, ..................

    1 mark · See worked answer →

  3. Q.2 (B)(iii) Find the 19th term of the following A.P. : 7, 13, 19, 25, ..........

    2 marks · See worked answer →

  4. Q.4 (ii) ₹ 2,000 is invested at 10 percent simple interest. Check at the end of the every year whether the interest amount is in A.P. or not. If this is an A.P., then find interest amount after 10 years.

    4 marks · See worked answer →

Maharashtra SSC Algebra (Mathematics Part I) Board Paper March 2024

Full paper →
  1. Q.1 (A)(iii) For an A.P., \(t_7 = 4\), \(d = -4\), then \(a\) = .........................

    1 mark · See worked answer →

  2. Q.1 (B)(ii) Find first term of the sequence \(t_n = 3n - 2\).

    1 mark · See worked answer →

  3. Q.2 (B)(iii) Find the 19th term of the following A.P. :

    7, 13, 19, 25, .......

    2 marks · See worked answer →

  4. Q.4 (iii) In a 'Mahila Bachat Gat' Kavita invested from the first day of month ₹ 20 on first day, ₹ 40 on second day and ₹ 60 on third day. If she saves like this, then what would be her total saving in the month of February 2020 ?

    4 marks · See worked answer →