If \(2k + 1\), 13 and \(5k - 3\) are three consecutive terms of an A.P., then \(k = \)

A. \(4\)

B. \(3\)

C. \(5\)

D. \(2\)

Doubtly AI Asked 24 Oct 2026 AI-verified · Oct 2026 ssc 10th Save WhatsApp Report

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Best answer

Answer: A. \(4\)

For an A.P., \(2 \times 13 = (2k + 1) + (5k - 3) \Rightarrow 26 = 7k - 2 \Rightarrow k = 4\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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