The sum of the present ages of a father and his son is 50 years. Five years ago, the father's age was 7 times the son's age. The father's present age is
A. 35 years
B. 42 years
C. 40 years
D. 45 years
A. 35 years
B. 42 years
C. 40 years
D. 45 years
Best answer
Answer: C. 40 years
Let the ages be \(F\) and \(S\). \(F + S = 50\) and \(F - 5 = 7(S - 5) \Rightarrow F = 7S - 30\). So \(8S - 30 = 50 \Rightarrow S = 10\), \(F = 40\).
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