Two dice are thrown simultaneously. The probability that the sum of the numbers on the upper faces is 7 is
A. \(\frac{7}{36}\)
B. \(\frac{5}{36}\)
C. \(\frac{1}{6}\)
D. \(\frac{1}{12}\)
A. \(\frac{7}{36}\)
B. \(\frac{5}{36}\)
C. \(\frac{1}{6}\)
D. \(\frac{1}{12}\)
Best answer
Answer: C. \(\frac{1}{6}\)
\(n(S) = 36\). Favourable: (1,6), (2,5), (3,4), (4,3), (5,2), (6,1), so \(P = \frac{6}{36} = \frac{1}{6}\).
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