Three coins are tossed simultaneously. The probability of getting at least two heads is

A. \(\frac{1}{2}\)

B. \(\frac{3}{8}\)

C. \(\frac{1}{8}\)

D. \(\frac{7}{8}\)

Doubtly AI Asked 24 Oct 2026 AI-verified · Oct 2026 ssc 10th Save WhatsApp Report

1 answer

Best answer

Answer: A. \(\frac{1}{2}\)

\(n(S) = 8\). At least two heads: HHT, HTH, THH, HHH, which is 4 outcomes. \(P = \frac{4}{8} = \frac{1}{2}\).

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report

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