If one root of \(x^2 + kx - 6 = 0\) is 2, then \(k = \)
A. \(-1\)
B. \(2\)
C. \(1\)
D. \(5\)
A. \(-1\)
B. \(2\)
C. \(1\)
D. \(5\)
Best answer
Answer: C. \(1\)
Substitute \(x = 2\): \(4 + 2k - 6 = 0 \Rightarrow 2k = 2 \Rightarrow k = 1\).
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