The value of g at a height equal to the radius of the earth (R) above its surface is
A. \(\frac{g}{4}\)
B. \(\frac{g}{2}\)
C. \(2g\)
D. \(g\)
A. \(\frac{g}{4}\)
B. \(\frac{g}{2}\)
C. \(2g\)
D. \(g\)
Best answer
Answer: A. \(\frac{g}{4}\)
\(g \propto \frac{1}{r^2}\). At height R, the distance from the centre is 2R, so g becomes \(\frac{g}{4}\).
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