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A frequency distribution table for the production of oranges of some farm owners is given below. Find the mean production of oranges by 'assumed mean' method.

A frequency distribution table for the production of oranges of some farm owners is given below. Find the mean production of oranges by 'assumed mean' method.

Production (Thousand rupees)25–3030–3535–4040–4545–50
No. of farm owners2025151010

1 answer

Answer: Mean production ≈ 35.31 thousand rupees, i.e. about ₹ 35,310

Take assumed mean \(A = 37.5\).

ClassClass mark \(x_i\)\(d_i = x_i - 37.5\)\(f_i\)\(f_id_i\)
25–3027.5-1020-200
30–3532.5-525-125
35–4037.50150
40–4542.551050
45–5047.51010100
Total\(\sum f_i = 80\)\(\sum f_id_i = -175\)

\[ \bar{d} = \frac{\sum f_id_i}{\sum f_i} = \frac{-175}{80} \approx -2.19 \]

\[ \bar{X} = A + \bar{d} = 37.5 + (-2.19) \]

\[ \bar{X} \approx 35.31 \]

Doubtly AI · 24 Oct 2026 AI-verified · Oct 2026 Report
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