Q.1 (A)(ii) One of the roots of equation x² + mx - 5 = 0 is 2, find the value of m . A. –2 B. -1/2 C. 1/2 D. 2

Answer: C. 1/2 Answer: (C) 1/2 Substitute x = 2 in x² + mx - 5 = 0 : 4 + 2m - 5 = 0 ⇒ 2m - 1 = 0 ⇒ m = 1/2 .

One of the roots of equation \(x^2 + mx - 5 = 0\) is 2, find the value of \(m\).

Q.1 (A)(ii) One of the roots of equation \(x^2 + mx - 5 = 0\) is 2, find the value of \(m\).

A. –2

B. \(-\dfrac{1}{2}\)

C. \(\dfrac{1}{2}\)

D. 2

Doubtly Asked 25 Oct 2026 ssc 10th Save WhatsApp Report

Best answer

Answer: C. \(\dfrac{1}{2}\)

Answer: (C) \(\dfrac{1}{2}\)

Substitute \(x = 2\) in \(x^2 + mx - 5 = 0\):

\(4 + 2m - 5 = 0 \Rightarrow 2m - 1 = 0 \Rightarrow m = \dfrac{1}{2}\).

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report

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