A person is standing at a distance of 80 m from a Church looking at its top. The angle of elevation is of 45º. Find the height of the Church.[Figure: right triangle with the church as the vertical side, the distance 80 m along the ground and the angl…

Q.2 (B)(v) A person is standing at a distance of 80 m from a Church looking at its top. The angle of elevation is of 45º. Find the height of the Church.

[Figure: right triangle with the church as the vertical side, the distance 80 m along the ground and the angle of elevation \(45^\circ\) at the observer.]

Doubtly Asked 25 Oct 2026 ssc 10th Save WhatsApp Report

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Answer: height of the church = 80 m

Let the height of the church be \(h\) metres and the distance of the person from its foot be 80 m. The triangle is right-angled at the foot of the church.

\(\tan 45^\circ = \dfrac{h}{80}\), and \(\tan 45^\circ = 1\).

\(\therefore h = 80 \times 1 = 80\) m.

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report

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A person is standing at a distance of 80 m from a Church looking at its top. The angle of elevation is of 45º. Find the height of the Church.[Figure: right triangle with the church as the vertical side, the distance 80 m along the ground and the angl…

1 answer

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