If both FeX2 & FeY3 are found to exist, X & Y can be : (1) X = F, Cl, Br, I Y = F, Cl, Br (2) X = Cl, Br,

If both FeX₂ & FeY₃ are found to exist, X & Y can be :

(1) X = F, Cl, Br, I :: Y = F, Cl, Br

(2) X = Cl, Br, I :: Y = F, Cl, Br, I

(3) X = F, Cl, Br :: Y = Cl, Br, I

(4) X = F, Cl, Br, I :: Y = F, Cl, Br, I

Doubtly Asked 16 Jul 2021 some-basic-concepts-of-chemistry-jee-main-2021 Save WhatsApp Report

1 answer

Best answer

(1) X = F, Cl, Br, I :: Y = F, Cl, Br is the correct option

Explaination::

FeI₃ does not exist as I^– reduces Fe³⁺ to Fe²⁺. 2Fe³⁺ + 2I – → 2Fe²⁺ + I₂.

Doubtly · 16 Jul 2021 Report