The orbit of a satellite is exactly 35780 km above the earth’s surface and its tangential velocity is 3.08 km/s.How much time the satellite will take to complete one revolution around the earth ?(Radius of earth = 6400 km.)

Q.3 (vii) The orbit of a satellite is exactly 35780 km above the earth’s surface and its tangential velocity is 3.08 km/s.
How much time the satellite will take to complete one revolution around the earth ?
(Radius of earth = 6400 km.)

Doubtly Asked 25 Oct 2026 ssc 10th Save WhatsApp Report

1 answer

Best answer

Answer: About 86,000 s, i.e. nearly 24 hours.

Radius of the orbit \(r = R + h = 6400 + 35780 = 42180\) km.

The satellite covers the circumference of the orbit in one revolution, so \(T = \dfrac{2\pi r}{v}\).

\[T = \frac{2 \times 3.142 \times 42180}{3.08} = \frac{265{,}000}{3.08} \approx 86{,}040\ \text{s}\]

\[T \approx \frac{86040}{3600} \approx 23.9\ \text{hours}\]

This is nearly one day — the period of a geostationary satellite.

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report

Was this answer helpful?

The orbit of a satellite is exactly 35780 km above the earth’s surface and its tangential velocity is 3.08 km/s.How much time the satellite will take to complete one revolution around the earth ?(Radius of earth = 6400 km.)

1 answer

Your answer