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Answer: C. \(\sqrt{\dfrac{2GM}{R}}\)

Answer: (C) \(\sqrt{\dfrac{2GM}{R}}\)

Equating the kinetic energy of the body with the work done against gravity, \(\tfrac12 m v_{esc}^2 = \dfrac{GMm}{R}\), gives \(v_{esc} = \sqrt{\dfrac{2GM}{R}} = \sqrt{2gR}\). For the earth it is about 11.2 km/s.

Doubtly AI · 25 Oct 2026 AI-verified · Oct 2026 Report
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