In Δ ABC, point D lies on side AB and point E lies on side AC (A–D–B and A–E–C) such that seg DE ∥ side BC. If AD = 6, DB = 9 and AE = 8, find EC.

Q.2 (B)(1) In Δ ABC, point D lies on side AB and point E lies on side AC (A–D–B and A–E–C) such that seg DE ∥ side BC. If AD = 6, DB = 9 and AE = 8, find EC.

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc 10th Save WhatsApp Report

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Answer: EC = 12

In Δ ABC, seg DE ∥ side BC.

∴ \(\dfrac{AD}{DB} = \dfrac{AE}{EC}\) (basic proportionality theorem)

\(\dfrac{6}{9} = \dfrac{8}{EC} \Rightarrow EC = \dfrac{8 \times 9}{6} = 12\).

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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In Δ ABC, point D lies on side AB and point E lies on side AC (A–D–B and A–E–C) such that seg DE ∥ side BC. If AD = 6, DB = 9 and AE = 8, find EC.

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