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Answer: Slope of AB = slope of BC = 2, so A, B, C are collinear.

Slope of AB \(= \dfrac{1 - (-1)}{2 - 1} = \dfrac{2}{1} = 2\).

Slope of BC \(= \dfrac{5 - 1}{4 - 2} = \dfrac{4}{2} = 2\).

Slopes of AB and BC are equal and point B is common to both lines, so points A, B and C are collinear.

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report
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