Calculate the osmotic pressure of solution containing 0.822 gm of sucrose in 300 mL of water at 298 K. [ Given : Molar mass of sucrose 342 g/mol, R = 0.08205 dm\(^3\) atm K\(^{-1}\) mol\(^{-1}\) ]

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Doubtly Asked 27 Oct 2026 Board exam · March 2026 hsc 12th Save WhatsApp Report

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Answer: \(\pi \approx 0.196\) atm

Moles of sucrose \(n = \dfrac{0.822}{342} = 2.404\times10^{-3}\) mol. Volume \(V = 300\) mL \(= 0.300\) dm\(^3\) (taking the volume of the solution as 300 mL).

\[\pi = \frac{n}{V}RT = \frac{2.404\times10^{-3}}{0.300}\times0.08205\times298 \approx 0.196\ \text{atm}\]

Doubtly AI · 27 Oct 2026 AI-verified · Oct 2026 Report

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Calculate the osmotic pressure of solution containing 0.822 gm of sucrose in 300 mL of water at 298 K. [ Given : Molar mass of sucrose 342 g/mol, R = 0.08205 dm\(^3\) atm K\(^{-1}\) mol\(^{-1}\) ]

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