If \(a + b + c = 6\), \(ab + bc + ca = 11\) and \(abc = 6\), find \(a^3 + b^3 + c^3\).
A. 18
B. 24
C. 54
D. 36
A. 18
B. 24
C. 54
D. 36
Best answer
Answer: D. 36
Answer: (D) 36
\(a^3 + b^3 + c^3 = (a + b + c)^3 - 3(a + b + c)(ab + bc + ca) + 3abc\).
\(= 216 - 3 \times 6 \times 11 + 3 \times 6 = 216 - 198 + 18 = 36\). (Check: a, b, c = 1, 2, 3 gives 1 + 8 + 27 = 36.)
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