If \(a + b + c = 9\) and \(ab + bc + ca = 23\), find the value of \(a^3 + b^3 + c^3 - 3abc\).

A. 81

B. 126

C. 207

D. 108

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc chsl Save WhatsApp Report

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Answer: D. 108

Answer: (D) 108

\(a^3 + b^3 + c^3 - 3abc = (a + b + c)\left[(a + b + c)^2 - 3(ab + bc + ca)\right] = 9(81 - 69) = 9 \times 12 = 108\).

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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