If x + y + z = 12 and xy + yz + zx = 44, what is the value of \(x^2 + y^2 + z^2\)?

A. 52

B. 60

C. 100

D. 56

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc cgl Save WhatsApp Report

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Answer: D. 56

Answer: (D) 56

\(x^2 + y^2 + z^2 = (x + y + z)^2 - 2(xy + yz + zx) = 144 - 88 = 56\).

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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