If a = 11 and b = 9, what is the value of \(\frac{a^2 + ab + b^2}{a^3 - b^3}\)?

A. 2

B. 20

C. \(\frac{1}{20}\)

D. \(\frac{1}{2}\)

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc cgl Save WhatsApp Report

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Answer: D. \(\frac{1}{2}\)

Answer: (D) \(\frac{1}{2}\)

\(a^3 - b^3 = (a - b)(a^2 + ab + b^2)\), so the expression = \(\frac{1}{a - b} = \frac{1}{2}\).

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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