If \((x - 2)^2 + (y - 3)^2 + (z - 4)^2 = 0\), what is the value of x + y + z?
A. 12
B. 9
C. 24
D. 0
A. 12
B. 9
C. 24
D. 0
Best answer
Answer: B. 9
Answer: (B) 9
A sum of squares is 0 only if each square is 0. So x = 2, y = 3, z = 4 and x + y + z = 9.
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