If a + b + c = 6, \(a^2 + b^2 + c^2 = 14\) and \(a^3 + b^3 + c^3 = 36\), what is the value of abc?

A. 12

B. 4

C. 6

D. 8

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc cgl Save WhatsApp Report

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Answer: C. 6

Answer: (C) 6

ab + bc + ca = \(\frac{36 - 14}{2}\) = 11.

\(a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - bc - ca)\) = 6 × (14 − 11) = 18.

So 36 − 3abc = 18 and abc = 6. (Check: a, b, c = 1, 2, 3.)

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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