If x + y + z = 0 and xy + yz + zx ≠ 0, what is the value of \(\frac{x^2 + y^2 + z^2}{xy + yz + zx}\)?

A. 2

B. 0

C. -1

D. -2

Doubtly AI Asked 27 Oct 2026 AI-generated · not yet verified ssc cgl Save WhatsApp Report

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Best answer

Answer: D. -2

Answer: (D) -2

\((x + y + z)^2 = 0\) gives \(x^2 + y^2 + z^2 = -2(xy + yz + zx)\).

So the ratio is −2.

Doubtly AI · 27 Oct 2026 AI-generated · not yet verified Report

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