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Answer: \(k=\frac{1}{21}\); \(P(X\lt 4)=\frac{2}{7},\ P(2\lt X\lt 4)=\frac{1}{7},\ P(X\gt 3)=\frac{5}{7}\)

(a) \(\Sigma P(X=x)=1\Rightarrow k+2k+3k+4k+5k+6k=21k=1\Rightarrow k=\frac{1}{21}\).

(b) \(P(X\lt 4)=P(1)+P(2)+P(3)=6k=\frac{6}{21}=\frac{2}{7}\)

\(P(2\lt X\lt 4)=P(X=3)=3k=\frac{3}{21}=\frac{1}{7}\)

\(P(X\gt 3)=P(4)+P(5)+P(6)=15k=\frac{15}{21}=\frac{5}{7}\)

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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