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Answer: \(C=2.655\times10^{-12}\) F \(\approx2.66\) pF

Given \(A=6\) cm2 \(=6\times10^{-4}\) m2, \(d=2\) mm \(=2\times10^{-3}\) m, \(\varepsilon_0=8.85\times10^{-12}\) C2/N m2.

For an air capacitor, \(C=\dfrac{\varepsilon_0A}{d}=\dfrac{8.85\times10^{-12}\times6\times10^{-4}}{2\times10^{-3}}\)

\(=8.85\times3\times10^{-13}=26.55\times10^{-13}=2.655\times10^{-12}\) F \(\approx2.66\) pF.

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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