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State any four uses of Van de Graaff generator. In a parallel plate air capacitor, intensity of electric field is changing at the rate of 2 \(\times\) 10\(^{11}\) V/ms. If area of each plate is 20 cm\(^2\), calculate the displacement current.

Q.31 State any four uses of Van de Graaff generator. In a parallel plate air capacitor, intensity of electric field is changing at the rate of 2 \(\times\) 10\(^{11}\) V/ms. If area of each plate is 20 cm\(^2\), calculate the displacement current.

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Answer: Displacement current \(I_d = 3.54 \times 10^{-3}\) A (3.54 mA).

Uses of Van de Graaff generator (any four):

  1. It produces very high potential differences (of the order of millions of volts).
  2. It is used to accelerate charged particles such as protons, deuterons and \(\alpha\)-particles to high energies.
  3. The high-energy particles are used to carry out nuclear disintegration experiments and to study nuclear structure.
  4. Accelerated particles (or X-rays produced by them) are used in medicine, e.g. for cancer treatment, and in research and industry (e.g. ion implantation).
  5. It is used to demonstrate electrostatic phenomena such as high-voltage discharge.

Numerical: Given \(\dfrac{dE}{dt} = 2 \times 10^{11}\) V m\(^{-1}\) s\(^{-1}\) (the paper’s “V/ms” means volt per metre per second), \(A = 20\) cm\(^2\) \(= 2 \times 10^{-3}\) m\(^2\).

Displacement current \(I_d = \varepsilon_0\dfrac{d\Phi_E}{dt} = \varepsilon_0 A\dfrac{dE}{dt}\):

\[I_d = 8.85 \times 10^{-12} \times 2 \times 10^{-3} \times 2 \times 10^{11} = 3.54 \times 10^{-3} \text{ A}\]
Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report
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