Calculate the current flowing through two long parallel wires carrying equal currents and separated by a distance of 1.35 cm experiencing a force per unit length of \(4.76\times10^{-2}\) N/m.

Q.25 Calculate the current flowing through two long parallel wires carrying equal currents and separated by a distance of 1.35 cm experiencing a force per unit length of \(4.76\times10^{-2}\) N/m.

Doubtly Asked 28 Oct 2026 Board exam · June 2026 hsc 12th Save WhatsApp Report

1 answer

Best answer

Answer: \(I\approx56.7\) A

Force per unit length between two long parallel wires: \(\dfrac{F}{l}=\dfrac{\mu_0I_1I_2}{2\pi d}\). With \(I_1=I_2=I\):

\(I^2=\dfrac{2\pi d}{\mu_0}\cdot\dfrac{F}{l}=\dfrac{2\pi\times1.35\times10^{-2}\times4.76\times10^{-2}}{4\pi\times10^{-7}}=\dfrac{1.35\times10^{-2}\times4.76\times10^{-2}}{2\times10^{-7}}\)

\(=\dfrac{6.426\times10^{-4}}{2\times10^{-7}}=3213\)

\(I=\sqrt{3213}\approx56.7\) A.

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report

Was this answer helpful?

Calculate the current flowing through two long parallel wires carrying equal currents and separated by a distance of 1.35 cm experiencing a force per unit length of \(4.76\times10^{-2}\) N/m.

1 answer

Your answer