Q.13 Identify ‘A’ and ‘B’ in the following reaction and rewrite the complete reaction : mathrmCH₃-CH=CH₂ xrightarrow[Peroxide]HBr A xrightarrow[-KBr]alcoholic\ KCN B

Identify ‘A’ and ‘B’ in the following reaction and rewrite the complete reaction :\(\mathrm{CH_3\text{-}CH=CH_2 \xrightarrow[Peroxide]{HBr} A \xrightarrow[-KBr]{alcoholic\ KCN} B}\)

Q.13 Identify ‘A’ and ‘B’ in the following reaction and rewrite the complete reaction :

\(\mathrm{CH_3\text{-}CH=CH_2 \xrightarrow[Peroxide]{HBr} A \xrightarrow[-KBr]{alcoholic\ KCN} B}\)

Doubtly Asked 28 Oct 2026 Board exam · March 2025 hsc 12th Save WhatsApp Report

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Answer: A = 1-bromopropane (CH₃CH₂CH₂Br); B = butanenitrile (CH₃CH₂CH₂CN)

In the presence of peroxide, HBr adds to propene against Markovnikov's rule (peroxide effect), giving 1-bromopropane. Alcoholic KCN then substitutes Br by CN.

\(\mathrm{CH_3\text{-}CH=CH_2 \xrightarrow[Peroxide]{HBr} \underset{(A)\ 1\text{-}bromopropane}{CH_3CH_2CH_2Br} \xrightarrow[-KBr]{alc.\ KCN} \underset{(B)\ butanenitrile}{CH_3CH_2CH_2CN}}\)

Doubtly AI · 28 Oct 2026 AI-verified · Oct 2026 Report

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Identify ‘A’ and ‘B’ in the following reaction and rewrite the complete reaction :\(\mathrm{CH_3\text{-}CH=CH_2 \xrightarrow[Peroxide]{HBr} A \xrightarrow[-KBr]{alcoholic\ KCN} B}\)

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